-8x^2-14x-3=0

Solution for -8x^2-14x-3=0 equation:

-8x^2-14x-3=0

a = -8; b = -14; c = -3;
Δ = b2-4ac
Δ = -142-4·(-8)·(-3)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-10}{2*-8}=\frac{4}{-16}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+10}{2*-8}=\frac{24}{-16}
=-1+1/2
$